## Is the number 27 rational or irrational?

27 is a rational number because it can be expressed as the quotient of two integers: 27 ÷ 1.

## Why is 27 a irrational number?

27 is not an irrational number because it can be expressed as the quotient of two integers: 27 ÷ 1.

**Is 27 a rational number?**

Answer. we know that root 3 is an irrational,so product of rational and irrational is also an irrational number. so aware root of 27 is an irrational number and 27 is a rational number.

### What is a square root of 27?

5.196

To obtain the square root of 27 in decimal form, substitute the approximate value of the square root of 3 in the radical form. √27 = 5.196. Therefore, the value of the square root of 27 in decimal form is 5.196 (approximately).

### Is the square root of 27 to the 3rd power rational?

No, because ∛27 = ∛(3 × 3 × 3) can be expressed in the form of p/q i.e. 3/1. Therefore, the value of the cube root of 27 is an integer (rational).

**Is the square root of negative 27 a real number?**

the square root of -27 is pure imaginary because of the square root of -1 which is i. Negative numbers don’t have ‘real’ square roots.

#### Which of the following is irrational number 27?

3 is rational but √3 is irrational so √27 is irrational no.

#### How do you make a perfect square of 27?

Explanation:

- 27 is not a perfect square so it does it have an exact square root.
- √27 is an irrational number, but it can be written in surd form:
- √27=√3×3×3.
- =3√3.

**What is root 27 as a power of 3?**

As the cube root of 27 is a whole number, 27 is a perfect cube….Cube root of 27 in radical form: ∛27.

1. | What is the Cube Root of 27? |
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3. | Is the Cube Root of 27 Irrational? |

4. | FAQs on Cube Root of 27 |

## What is the 3rd square root of 27?

## Is cube root of 27 rational or irrational?

The value of the cube root of 27 can be expressed in the form of p/q i.e. = 3/1, where q ≠ 0. Therefore, the ∛27 is rational.

**Is 27 3 A irrational number?**

It’s irrational because it cannot be represented in the form of p/q.